Russian ironman Daniil Medevdev has ended Alex de Minaur’s US Open marketing campaign with a signature fourth-round victory in New York.
De Minaur performed some impressed attacking tennis early to boost hopes of an upset win earlier than the third-seeded 2021 Open champion powered to a 2-6 6-4 6-1 6-2 triumph.
Australia’s world No.13 had been bidding to make the quarter-finals at Flushing Meadows for a second time however couldn’t stick with Medvedev after dropping a decent second set.
De Minaur’s departure ends Australia’s participation within the singles, with the 24-year-old having to accept a probable rankings rise to a career-high No.12 subsequent Monday.
Runner-up in 2019 earlier than denying Novak Djokovic a calendar-year grand slam sweep two years in the past, Medvedev advances to an all-Russian quarter-final towards eighth seed Andrey Rublev.
That didn’t look on the playing cards early towards de Minaur, whose aggressive play had the previous world No.1 rattled and made a repeat of his win over Medvedev in Toronto final month appear a definite chance.
Playing aggressive tennis, de Minaur gained 9 of 9 factors speeding the web and broke Medvedev within the fifth and seventh video games to steam by the opening set in 32 minutes.
But a spectacular tweener from Medvedev throughout a 34-shot profitable rally sparked the Russian into motion halfway by the second set.
De Minaur needed to battle off 5 break factors to carry for 2-2 however couldn’t get well from 15-40 down serving at 4-5 as Medvedev levelled the match at a set apiece.
The Russian shifted up a gear within the fourth, overpowering de Minaur from the again with two extra breaks to take a two-sets-to-one lead.
It was all however over when de Minaur dropped serve twice extra within the fourth set as Medvedev surged to 5-1 earlier than closing out the competition after two hours and 40 minutes.
Source: www.perthnow.com.au
